x=13.5
20 and the vertex of the parabola is at (3, 20)
The vertex is (-9, -62).
y=2x^2+20x+7 y=ax^2+bx+c a=2; b=20; c=7 x-coordinate of the vertex is : -b/2a = -20/2(2) = -20/4 = -5 y-coordinate of the vertex = 2(-5)^2+20(-5)+7 = 2(25)-100+7 =50-100+7 = -43 The vertex is(-5,-43)
The vertex is at (-1,0).
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
20 and the vertex of the parabola is at (3, 20)
The vertex is (-9, -62).
y=2x^2+20x+7 y=ax^2+bx+c a=2; b=20; c=7 x-coordinate of the vertex is : -b/2a = -20/2(2) = -20/4 = -5 y-coordinate of the vertex = 2(-5)^2+20(-5)+7 = 2(25)-100+7 =50-100+7 = -43 The vertex is(-5,-43)
The vertex is at (-1,0).
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
The vertex has a minimum value of (-4, -11)
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
The equation is linear and so has no vertex.
(-4,-1)
The vertex is at the point (0, 4).
20
The sum of 20 added to itself 20 times is calculated by multiplying 20 by 20, resulting in 400. Therefore, the answer to the given equation is 400.