x2 + 8x + 15 = (x + 3) (x + 5).
The vertex has a minimum value of (-4, -11)
Forget about thw value of pi because it has nothing to do with the question. y = x2-8x+1 can be expressed as y = (x-4)2-15 Information about the vertex and line of symmetry can be extracted from the rearranged equation such as:- Vertex: (4, -15) Line of symmetry: x = 4
(x+5)(x+3)
(x - 3)(x - 5)
x2 + 8x + 15 = (x + 3)(x + 5)
x2 + 8x + 15 = (x + 3) (x + 5).
The vertex has a minimum value of (-4, -11)
x2-8x+15 = (x-3)(x-5)
x² + 8x + 15 = (x + 5)(x + 3)
Forget about thw value of pi because it has nothing to do with the question. y = x2-8x+1 can be expressed as y = (x-4)2-15 Information about the vertex and line of symmetry can be extracted from the rearranged equation such as:- Vertex: (4, -15) Line of symmetry: x = 4
X2 - 8X + 15 = (X - 3)(X - 5)
(x+5)(x+3)
Y = X2 - 8X + 12set to 0X2- 8X + 12 = 0X2 - 8X = - 12halve the coefficient of the linear term, ( - 8 ), square it and add it to both sidesX2 - 8X + 16 = - 12 + 16factor on the left and gather term on the right(X - 4)2 = 4(X - 4)2 - 4 = 0================vertex form(4, - 4)=======vertex
X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16
(x - 3)(x - 5)
x^2-8x+3 = x^2-8x+16-16+3 = (x-4)^2-13 y=(x-4)^2 -13 The vertex is (4,-13).