20 and the vertex of the parabola is at (3, 20)
y=2x^2+20x+7 y=ax^2+bx+c a=2; b=20; c=7 x-coordinate of the vertex is : -b/2a = -20/2(2) = -20/4 = -5 y-coordinate of the vertex = 2(-5)^2+20(-5)+7 = 2(25)-100+7 =50-100+7 = -43 The vertex is(-5,-43)
The vertex is (-9, -62).
The vertex is at (-1,0).
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
20 and the vertex of the parabola is at (3, 20)
y=2x^2+20x+7 y=ax^2+bx+c a=2; b=20; c=7 x-coordinate of the vertex is : -b/2a = -20/2(2) = -20/4 = -5 y-coordinate of the vertex = 2(-5)^2+20(-5)+7 = 2(25)-100+7 =50-100+7 = -43 The vertex is(-5,-43)
The vertex is (-9, -62).
The vertex is at (-1,0).
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
The vertex has a minimum value of (-4, -11)
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
The equation is linear and so has no vertex.
(-4,-1)
The vertex is at the point (0, 4).
20
20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 = 400.