Since the diameter is 48 inches, and there are 8 sides, then each side will be 48/8 = 6 inches.
An octagon is a polygon with 8 sides. To find the diameter of a regular octagon when each side is 18 inches in length, you can use the formula: Diameter = Side length × √(2 + √2) Plugging in the given side length (18 inches): Diameter = 18 × √(2 + √2) ≈ 56.97 inches So, the diameter of the octagon is approximately 56.97 inches.
An octagon is an eight-sided figure. If a regular octagon has a perimeter of 24 inches, then each side will be 24 / 8 = 3 inches.
Approx 3.83 feet.
4.14 feet, approx.
The perimeter of an octagon that has one side of 2 inches is 16 inches.
The inradius (apothem) is 38.63 inches. The circumradius is 41.81 inches.
The length of a single edge of an octagon can be calculated by measuring the diameter, then dividing this length by the square root of the sum of four and two times the square root of two, which would be written in a calculator as sqrt(4+(2*sqrt(2))). In this case, a five inch diameter equates to approximately 1.913 inches per side.
if there 8 sides on an octagon then 8 times 4 should give you your answer which is ....... 32
A regular octagon has 8 sides so if each side is 3 1/2 inches long then the perimeter is just 8*(3 1/2 inches) or 28 inches
The side length is 2/[cos(pi/4)*cos(pi/8)] = 3.06 inches, approx.
8 sides each 9 inches: 6 feet