Q: What is the sum of y and 10 divided by 2 ?

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the answer is y minus 10 divided by 2.

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

2(2+Y)

2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y

x = 10, y = 25

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2.5

2x / (y-2) + 2x / (2-y)First get a common denominator: (y-2) (2-y)Then you have:2x(2-y) / (y-2)(2-y) + 2x(y-2) / (y-2)(2-y), summing and simplifying, you get:(4x-4) / (y-2)(2-y)

1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.

the answer is y minus 10 divided by 2.

x+y=18x^2+y^2=164 x=10 and y=8 or vice versa

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

This question can not be solved

0.5

Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)

17

2(2+Y)

2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y