wat is the whole problem that actually it is 42
(-x)/(-y) = x/y as long as y does not equal 0 in which case it is undefined. x/y cannot be simplified further unless you are given values for x or y or both. For example, if x = 10 and y = 5 then x/y can be simplified to 10/5 = 2.
X/3+Y There is no answer unless its equal to something X/3+Y=0 for example, or you have a value for the variables (1)/3+(2).
-1
1/x = y x = 1/y
Y / (2+x)If x = -1 and y=2, thenY / (2+x) = 2/(2-1) = 2/1 = 2
wat is the whole problem that actually it is 42
y=(x+2)/(x+10) xy+10y=x+2 xy-x=2-10y x(y-1)=2-10y x=(2-10y)/(y-1)
(-x)/(-y) = x/y as long as y does not equal 0 in which case it is undefined. x/y cannot be simplified further unless you are given values for x or y or both. For example, if x = 10 and y = 5 then x/y can be simplified to 10/5 = 2.
if INVERSELY proportional then y = 1/X^2 ( that is, 1 divided by x squared) If X doubles then X SQUARED increases as 2 x 2 = 4 times SINCE Y = 1/x^2 then Y DECREASES 4 times
y = x / (x^2 + 2x + 1) The horizontal asymptote is y = 0
It is x^2 + xy + y^2
When dividing fractions, multiply by the inverse of the fraction.That is, a/b divided by x/y = a/b times y/x = ay/bxFor example,2/5 divided by 3 = 2/5 x 1/3 = 2/152/5 divided by 1/3 = 2/5 x 3/1 = 6/55 divided by 3 = 5/1 x 1/3 = 5/35 divided by 1/3 = 5/1 x 3/1 = 15/1 (= 15)
X = 17.7 + 0.1y
y = square root of x y = x(1/2) y' = (1/2)x(1/2 - 1) y' = (1/2)x(-1/2) y' = (1/2)(square root of x)
X^4 divided by Y^2
y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X