the answer is y minus 10 divided by 2.
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
2(2+Y)
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
x = 10, y = 25
To find 2 times the sum of y and 5, you first need to calculate the sum of y and 5 by adding y and 5 together. Once you have the sum, you then multiply it by 2 to find the final result. The expression for this calculation would be 2(y + 5).
2.5
2x / (y-2) + 2x / (2-y)First get a common denominator: (y-2) (2-y)Then you have:2x(2-y) / (y-2)(2-y) + 2x(y-2) / (y-2)(2-y), summing and simplifying, you get:(4x-4) / (y-2)(2-y)
1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
x+y=18x^2+y^2=164 x=10 and y=8 or vice versa
the answer is y minus 10 divided by 2.
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
0.5
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
2(2+Y)
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
Sum = addition Difference = subtraction Say your first number is x and your second number is y. So: x+y = 10 and x-y = 20 Solve for one variable for one of the above equations and substitute that variable into the other equation: x = 10-y (10-y)-y = 20 10-2y = 20 Get y by itself: -2y = 20-10 -2y = 10 Solve for y: -2y/-2 = 10/-2 y = -5 To solve for x: x = 10-y x = 10-(-5) x = 10+5 x = 15 Therefore, the two numbers you are looking for are -5 and 15.