x+y=18x^2+y^2=164
x=10 and y=8 or vice versa
5
3 and 5
The numbers are 12 and 14.
5 5+4 = 9 52+42 = 41
To find the median with two numbers, do as you would to find the "average" or the "mean" by finding the sum between the two numbers and dividing the sum (or total) by two.
Sum of squares? Product?
82 + 102 = 64 + 100 = 164
Let the two consecutive positive numbers be ( x ) and ( x + 1 ). The equation for the sum of their squares is ( x^2 + (x + 1)^2 = 164 ). Simplifying this gives ( x^2 + x^2 + 2x + 1 = 164 ), or ( 2x^2 + 2x - 163 = 0 ). Solving this quadratic equation, we find ( x = 9 ) and ( x + 1 = 10 ). Thus, the two consecutive positive numbers are 9 and 10.
To get a list of the squares of the first 1000 numbers we can do:> [n^2 | n sum [n^2 | n
The sum of their squares is 10.
Find the two numbers with the largest magnitudes (absolute values). The sum of their squares will be the maximum.
split 10 in two parts such that sum of their squares is 52. answer in full formula
The two numbers are 9 and 13.
Not unless at least one of the numbers is zero.
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
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