Start with 1, go from there.... you'll find them all eventually.
-- method -- We need X numbers which are consecutive, so the middle number will be 1/ X of the total. Divide the sum of the numbers by the number of numbers ... in this case divide 186 by 3. The numbers are to be consecutive and even, so subtract 2 from the number go get one of the numbers and add 2 to the number to get the other number. You now have three numbers which are even and consecutive. Now, place a minus sign in front of them, to turn them into negative numbers For instance 12, 14 and 16 are three consecutive numbers whose sum is 42. -12, -14 and - 16 are three consecutive even integers whose sum is -42 Now you know all you need to solve the problem.
Let n be the first integer, then n+1, n+2 and n+3 are the other three integers We have 4n+6=244 or 4n=238 but 4 does not go into 238 evenly so we CAN'T find 4 integers that work!
Yes, it's even.
There are two ways to approach this. You could use odd integers larger or smaller than -3. If you go larger than -3, the answer is: -3, -1, 1, 3, 5. If you go smaller than -3, the answer is: -3, -5, -7, -9, -11.
2,3,4 is not 4,5,6 is not 6,7,8 is not I could go on
There is no set of five consecutive integers that are factors of 700. The positive integer factors of 700 are the following: 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 140, 175, 350, 700
Infinity!! For Ex:- between 2 & 3 2.1 , 2.2 ......2.9 then adding one more decimal value:- 2.11, 2.12 ,2.13........go on forever.
There is no set of three consecutive numbers totaling 170.
YES
Yes. They went to consecutive National Championships in 1991 and 1992.
Not possible unless you go into decimals. Even then I'm not sure if it's possible. 46 = 13+15+17.