1 and 2
4 and 5
Start with 1, go from there.... you'll find them all eventually.
-- method -- We need X numbers which are consecutive, so the middle number will be 1/ X of the total. Divide the sum of the numbers by the number of numbers ... in this case divide 186 by 3. The numbers are to be consecutive and even, so subtract 2 from the number go get one of the numbers and add 2 to the number to get the other number. You now have three numbers which are even and consecutive. Now, place a minus sign in front of them, to turn them into negative numbers For instance 12, 14 and 16 are three consecutive numbers whose sum is 42. -12, -14 and - 16 are three consecutive even integers whose sum is -42 Now you know all you need to solve the problem.
Let n be the first integer, then n+1, n+2 and n+3 are the other three integers We have 4n+6=244 or 4n=238 but 4 does not go into 238 evenly so we CAN'T find 4 integers that work!
Yes, it's even.
There are two ways to approach this. You could use odd integers larger or smaller than -3. If you go larger than -3, the answer is: -3, -1, 1, 3, 5. If you go smaller than -3, the answer is: -3, -5, -7, -9, -11.
2,3,4 is not 4,5,6 is not 6,7,8 is not I could go on
No, 80 cannot go into 50. Since 80 is greater than 50, it cannot fit into it even once. In mathematical terms, 50 divided by 80 results in a fraction less than one.
There is no set of five consecutive integers that are factors of 700. The positive integer factors of 700 are the following: 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 140, 175, 350, 700
Well, honey, if you're looking for a pair of consecutive integers that add up to 45, then it's simple math. Just take 22 and 23. Those two bad boys will give you a total of 45. So there you have it, now go impress someone with your newfound integer knowledge.
Infinity!! For Ex:- between 2 & 3 2.1 , 2.2 ......2.9 then adding one more decimal value:- 2.11, 2.12 ,2.13........go on forever.
There is no set of three consecutive numbers totaling 170.
YES