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The product of 2 consecutive odd integers when they equal 35?
what is the formula to use to solve the product of two consecutive odd integers
How would you find four consecutive even integers whose sum is four?
You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.
How do you find four consecutive integers with the sum of 138?
The simplest way is to solve 4n + 6 = 138 for the smallest of them.
Find 2 consecutive integers whose difference is 2?
no solution. If you solve for x (where x is the first integer) the answer is a fraction, which is not an integer.
How to solve the sum of two consecutive integers is 45?
Let x = one of the integers x + 1 = the other integer x + x + 1 = 45 2x = 44 x = 22 x + 1 = 23
