answersLogoWhite

0


Best Answer

62

User Avatar

Wiki User

8y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What 2 digit number has a remainder of 2 when divided by 3 4 5 or 6?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What am ii am a two digit number when divided by2345 there is remainder of one?

A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.


What two-digit number can be divided by 2 with a remainder of 1 and divided by three with a remainder of 2?

17


What two digit number when divided will result in a remainder of 1?

Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.


Can a remainder be a 2 digit number?

Yes- A remainder can be any number less than the dividend (the number by which the divisor is divided). An example of a 2 digit number is: 131/11=11 remainder 10.


What is the largest 3 digit number when divided by 2 the quotient is 3 digit and the remainder is 6?

You can't have a remainder of 6 when you divide by 2! JHC!


What is the largest 3 digit even number that can be divided by 2 without remainder?

1.5


What is the largest 3 digit number that leaves a remainder of 2 when divided by 5?

It is 997.


What is the largest 2 digit number that leaves a remainder of 3 when divided by 4?

99


Jane has found a two digit number that has a remainder of 2 weather divided by 345 or 6?

This is impossible. A two digit number n divided by 345 has a remainder equal to n. If you meant to say divided by 3,4,5 or 6 then the answer is 62.


What is the remainder of 245 divided by 9?

27.2222


What is the smallest three-digit number that gives a three-digit quotient and a remainder of 2 when divided by 4?

-2


Is 60 divisible by 8?

2 x 6 + 0 = 12 2 x 1 + 2 = 4 4 is not [divisible by] 8, so 60 is not divisible by 8. (The remainder when 60 is divided by 8 is 4). To test divisibility by 8: Add together the hundreds digit multiplied by 4, the tens digit multiplied by 2 and the units (ones) digit. If this sum is divisible by 8 so is the original number. (Otherwise the remainder of this sum divided by 8 is the remainder when the original number is divided by 8.) If you repeat this sum on the sum until a single digit remains, then if that digit is 8, the original number is divisible by 8 otherwise it gives the remainder when the original number is divided by 8 (except if the single digit is 9, in which case the remainder is 9 - 8 = 1).