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The expected number of rolls under 3 is the number of rolls times the probability of rolling less than 3. So: E(rolls less than 3 out of 30) = 30 * 1/3 = 30/3 = 10
pr(six) = 1/6 → expected 6s in 90 rolls = 1/6 × 90 = 15
You will roll 600 times, of course!
60
Total possible outcomes of one roll = 6Number of primes on the die = 3 (2, 3, and 5)Probability of a prime on each roll = 3/6 = 50% .So, in 300 rolls of a fair die, you would expect approximately 150 primes.
If George rolls the die 300 times, how many fives will he roll?
The expected number of rolls under 3 is the number of rolls times the probability of rolling less than 3. So: E(rolls less than 3 out of 30) = 30 * 1/3 = 30/3 = 10
With 1000 rolls of a die, and each number having a probability of 1/6, I would not expect any peaks.
pr(six) = 1/6 → expected 6s in 90 rolls = 1/6 × 90 = 15
You will roll 600 times, of course!
The probability of rolling a four on a single roll of a fair die is 1/6. So the expected number of 4s in 450 rolls is 450*1/6 = 75.
Possible outcomes of one roll = 6Successful outcomes = 1Probability of success on each roll = 1/6Expectation in 150 rolls = (1/6) x (150) = 25 times
Exactly 14,320 ½ times.
2 times
You can expect to get a 5 about 15 times out of 90.
With a fair die, you would expect it 60*(1/6) = 10 times.
Approximately 31 times