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The equation p1v1 t1 equals p2v2 t2 is known as the what?
Avogardo's Law
Find the common ratio of the following geometric sequence 2.512 11.304 50.868 228.906 1030.077?
Formula for the nth term of general geometric sequence tn = t1 x r(n - 1) For n = 2, we have: t2 = t1 x r(2 - 1) t2 = t1r substitute 11.304 for t2, and 2.512 for t1 into the formula; 11.304 = 2.512r r = 4.5 Check:
What is the nth term formula of 100 96 92 and 88?
Since the difference of any two consecutive numbers (the common difference) is 4 (a constant), then this sequence is an arithmetic sequence. Let's take a look at this sequence: t1 = 100 t2 = t1 - 4 = 100 - 4 = 96 t3 = t2 - 4 = 96 - 4 = 92 t4 = t3 - 4 = 92 - 4 = 88 Thus, the formulas t1 = 100 and tn = t(n-1) - 4 gives a recursive definition for the sequence 100, 96, 92, 88.
Please list the sample space for flipping a coin and rolling a number cube with 1 2 3 4 5 and 6?
Flipping a coin: two possible outcomes, H or T. Rolling a die: six possible outcomes, 1, 2, 3, 4, 5, or 6. Flipping a coin and rolling a die: 12 possible outcomes. So the sample space has 12 outcomes such as, {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6 }
What is the answer for finding the sum of the arithmetic sequence with a sigma notation with a 25 on top and t1 on the bottom then 5t-3 on the rightside?
To find the sum of 25 terms of these arithmetic sequence you can use the formula:Sn = (n/2)(a1 + an), where n is the number of terms in the sequence, a1 is the first term, and an is the last term of the sequence. In our case n = 25, so we need to compute a1 and a25.Since an = 5t - 3, thena1 = 5(1) - 3 = 5 - 3 = 2a25 = 5(25) - 3 = 125 - 3 = 122By substituting the values we know into the formula we have:S25 = (25/2)(2 + 122) = (25/2)(124) = 25 x 62 = 1,550Or you can use the formula:Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference.In order to find d, we need to find at least the value of 2 terms and subtract them.a1 = 2a2 = 5(2) - 3 = 10 - 3 = 7So d = 7 - 2 = 5By substituting the values we know into the formula we have:S25 = (25/2)[2(2) + (25 - 1)5]S25 = (25/2)(4+ 120) = (25/2)(124 = 25 x 62 = 1,550Thus, the sum of 25 terms of the given arithmetic sequence is 1,550.
The equation p1v1 t1 equals p2v2 t2 is known as the what?
Avogardo's Law
Which equation represent combined gas law?
The general representation of the combined gas law is P1V1/T1 = P2V2/T2
How do you find T2 of the combined gas law?
The Combined Gas Law relates pressure (P), volume (V) and temperature (T). The appropriate SI units are P in atm, V in liters, and T in degrees Kelvin. The Combined Gas Law equation is (P1*V1)/T1 = (P2V2)/T2. Isolating for V2 the equation then becomes (P1V1T2)/(T1P2) = V2
Why is you cold in the Alps?
Because it is so high up the air. Pressure up there is high and temperature therefore low if you use P1V1/T1= P2V2/T2
A sample of oxygen gas has a volume of 150 milliliters at 300k if the pressure of the sample is held constant and the temp raised to 600k the new sample will be?
Using the combined gas law (P1V1/T1 = P2V2/T2), we can calculate the new volume of the oxygen gas sample at 600K. Given P1V1/T1 = P2V2/T2, we have P1 = P2 (pressure is constant), V1 = 150 mL, T1 = 300K, and T2 = 600K. Plugging in these values, we get V2 = (P1 * V1 * T2) / (T1) = (1 * 150 * 600) / (300) = 300 mL. So, the new volume of the oxygen gas sample at 600K would be 300 milliliters.
What do you expect to happen to the volume of the gas if its pressure is doubled and its temperature is reduced to half?
From Boyle ideal gas law P1V1/T1 = P2V2/T2 so volume is reduced by a factor of 4
What is the origvol of gas if the gas press is 135kpa with a temp of 295a gas volume of 575l a press of 105ka temp of270k?
To find the original volume of gas, you can use the combined gas law equation: (P1V1)/T1 = (P2V2)/T2. Plug in the given values to solve for the original volume, where P1 = 135 kPa, V1 = 575 L, T1 = 295 K, P2 = 105 kPa, and T2 = 270 K. Solving for V1 will give you the original volume of the gas.
What pressure in atmospheres is required to compress 6.25 L of gas at STP to a volume of 2.875 L?
Using the combined gas law, we can find the pressure by setting up the equation: P1V1/T1 = P2V2/T2. At STP, T1 = T2, so the equation simplifies to P1V1 = P2V2. Plugging in the values, we get P1 = (2.875 L * 1 atm) / 6.25 L = 1.38 atm.
What is the volume of gas at 250 degrees Celsius as compared with the volume at 0 degrees Celsius?
P1V1/T1 = P2V2/T2Assuming only temperature and volume are changing and pressure will be kept constant:V1/T1 = V2/T2Only Kelvin can be usedV1/273 = V2/523Assume the volume at 0 ºC is 1 unit thenV2 = 1.92 units
What is a fixed mass of gas is at a pressure of 7.00 atmospheres at 379 K in 2.00 liters what is the pressure at 425 K temperature and the same volume?
If it is an Ideal Gas, then you can use: P1V1/T1 = P2V2/T2, and since volume is constant, you have P1/T1 = P2/T2, where P is pressure and T is absolute temperature, and the subscripts refer to the 1st state and the 2nd state of the gas.So: (7.00 atm)/(379 K) = P2/(425 K), solve for P2 =(425 K)(7.00 atm)/(379 K)= 7.85 atm
What volume will 400 ml of argon gas initially at 30 degree celsius and 725 mmHg occupy at 30 degree celsius and 650 mmhg?
The volume is 0,446 L.
A sample of helium gas has a volume of 900 milliliters and pressure of 2.50 ATM at 298k what is the new pressure when the temoerature is changed to 336 k and the volume is decreased to 450 milliliters?
Using the combined gas law, we can calculate the new pressure. The initial conditions are V1 = 900 mL, P1 = 2.50 ATM, and T1 = 298 K. The final conditions are V2 = 450 mL, T2 = 336 K. Using P1V1/T1 = P2V2/T2, we can solve for the new pressure, which is around 3.33 ATM.
