To find the sum of 25 terms of these arithmetic sequence you can use the formula:
Sn = (n/2)(a1 + an), where n is the number of terms in the sequence, a1 is the first term, and an is the last term of the sequence. In our case n = 25, so we need to compute a1 and a25.
Since an = 5t - 3, then
a1 = 5(1) - 3 = 5 - 3 = 2
a25 = 5(25) - 3 = 125 - 3 = 122
By substituting the values we know into the formula we have:
S25 = (25/2)(2 + 122) = (25/2)(124) = 25 x 62 = 1,550
Or you can use the formula:
Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference.
In order to find d, we need to find at least the value of 2 terms and subtract them.
a1 = 2
a2 = 5(2) - 3 = 10 - 3 = 7
So d = 7 - 2 = 5
By substituting the values we know into the formula we have:
S25 = (25/2)[2(2) + (25 - 1)5]
S25 = (25/2)(4+ 120) = (25/2)(124 = 25 x 62 = 1,550
Thus, the sum of 25 terms of the given arithmetic sequence is 1,550.
yes. When you are finding the area of a triangle you do the same for all types of triangles.
It means you are finding what number multiplied by itself will give you the number you are finding the square root of.
The difference between 24 and 14 is 10. This is calculated by subtracting 14 from 24, which equals 10. In mathematical terms, the formula for finding the difference between two numbers is subtracting the smaller number from the larger number.
The only significant difference that I know of is that there is a method, somewhat like long division, that can be used for finding the square root. I am not aware of a similar process for a cube root.
Finding the point of intersection using graphs or geometry is the same as finding the algebraic solutions to the corresponding simultaneous equations.
The nth term of an arithmetic sequence = a + [(n - 1) X d]
You didn't say the series (I prefer to use the word sequence) of even numbers are consecutive even numbers, or even more generally an arithmetic sequence. If we are not given any information about the sequence other than that each member happens to be even, there is no formula for that other than the fact that you can factor out the 2 from each member and add up the halves, then multiply by 2: 2a + 2b + 2c = 2(a + b + c). If the even numbers are an arithmetic sequence, you can use the formula for the sum of an arithmetic sequence. Similarly if they are a geometric sequence.
This is an arithmetic sequence with the first term t1 = 1, and the common difference d = 6. So we can use the formula of finding the nth term of an arithmetic sequence, tn = t1 + (n - 1)d, to find the required 30th term. tn = t1 + (n - 1)d t30 = 1 + (30 - 1)6 = 175
10n + 1
Assuming the sequence does not merely skip from 13 to 49, and instead carries on in the same pattern, the sequence proceeds thus:1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45, 49.This is thirteen terms. The formula for finding these terms is 4x-3.
RAMANUJANRAMANUJAN
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
0,1,1,2,3,5,8,13
The formula for finding the midpoint of a line segment using midpoint notation is: M ((x1 x2) / 2, (y1 y2) / 2)
The Big O notation for finding the complexity of algorithms that involve both finding the character 'c' and 'k' in a given input is O(n), where n is the length of the input.
There is no set equation for finding the nth term of a non- linear sequence. You have to go through a procedure to find the equation suitable for your given sequence. You would have to post the equation itself or re phrase your question for the answer.
by finding decimals i guess