let the three consecutive no.s be k-1,k and k+1,where k is a positive whole no.
so (k-1)+k+(k+1)=135 according to the question
or, 3k=135
or, k=45
which gives the no.s as 44,45,46 44+45+46=135
44,45,46
44 + 45 + 46 = 135
44 + 45 + 46 = 135
The three smallest consecutive odd numbers starting from 135 are 135, 137, and 139. These numbers are all odd and follow each other consecutively.
44,45,46
The numbers are 135 and 136.
137
134 and 135
138
Those three odd integers are 43, 45, and 47.
Let's call the three consecutive integers x, x+1, and x+2. The sum of these integers is x + (x+1) + (x+2) = 3x + 3. We know that this sum is equal to 135, so we can set up the equation 3x + 3 = 135. Solving for x gives us x = 44. Therefore, the three consecutive integers are 44, 45, and 46.
Given the sum of three consecutive integers 135, we write out the expression as:x + (x + 1) + (x + 2) = 135 where:x = smallest integerx + 1 = middle integerx + 2 = largest integerSolve for x by rearranging the terms:3x + 3 = 1353x = 132x = 44Therefore, the largest integer is x + 2 = 46.