44 + 45 + 46 = 135
44 + 45 + 46 = 135
44,45,46
let the three consecutive no.s be k-1,k and k+1,where k is a positive whole no. so (k-1)+k+(k+1)=135 according to the question or, 3k=135 or, k=45 which gives the no.s as 44,45,46 44+45+46=135
The numbers are 135 and 136.
134 and 135
137
138
The integers are 44, 45 and 46.
Those three odd integers are 43, 45, and 47.
139 + 135 +137 = 411
108 117 126 135 144 153 and 162