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118

The integers are 27, 28, 29 and 30.

27+28+29+30=114

27 + 28 + 29 + 30 = 114

27 28 29 30

The integers are 37, 38 and 39.

There is no set of six consecutive integers for -4.

27, 28, 29 and 30.

The consecutive odd integers for 114 are 37, 38 and 39.

117

114/4 = 28.5 So the 4 numbers are 27, 28, 29 and 30

The numbers are 56 and 58.

27, 28, 29 and 30

Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.

114/3 = 38, so the three integers are 37, 38 and 39.

There is not such set of integers.

The larger is 114, and the other is 112.

The consecutive even integers beginning with -4 are: -4, -2, 0, 2

-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.

The numbers are 27, 28, 29 and 30.

Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35

There are four consecutive odd integers: 81, 83, 85 and 87.

There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.

26 is the largest

-4 and -5