27 + 28 + 29 + 30 = 114
The numbers are 27, 28, 29 and 30.
There are four consecutive odd integers: 81, 83, 85 and 87.
There are no such numbers. If S is the sum of any 4 consecutive integers then S = 2 (mod 4) In other words, any four consecutive integers add up to an even number that is NOT dvisible by 4.
10
The integers are 3, 4, 5 and 6.
118
The integers are 27, 28, 29 and 30.
27+28+29+30=114
27 + 28 + 29 + 30 = 114
27 28 29 30
The integers are 37, 38 and 39.
27, 28, 29 and 30.
114/4 = 28.5 So the 4 numbers are 27, 28, 29 and 30
The consecutive odd integers for 114 are 37, 38 and 39.
There is no set of six consecutive integers for -4.
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
The numbers are 56 and 58.