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27 + 28 + 29 + 30 = 114

118

The numbers are 27, 28, 29 and 30.

The integers are 37, 38 and 39.

The four consecutive integers with the sum of -66 are -18, -17, -16 and -15.

The integers are 27, 28, 29 and 30.

117

27+28+29+30=114

The numbers are 56 and 58.

The smallest is -1

The sum of the first four non-negative, consecutive, even integers is 20.

If n is the smallest of the four integers, their sum is 4n+6.

No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.

There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.

14, 15, 16 and 17.

The consecutive odd integers for 114 are 37, 38 and 39.

They are odd consecutive integers: 21, 23, 25 and 27.

6,7,8,9

There are none.

15,16,17,18

27 28 29 30

The larger is 114, and the other is 112.

The sum is four.

There are four consecutive odd integers: 81, 83, 85 and 87.

-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.