4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96
360
Numbers that are divisible by both 6 and 8 must be multiples of the least common multiple of 6 and 8, which is 24. Therefore, numbers that are divisible by both 6 and 8 are any multiples of 24. These numbers include 24, 48, 72, 96, and so on.
Lots and lots of them are. But a good way to determine which ones are is to multiply 3 x 8, which = 24. Then you can multiply 24 x 3 or 24 x 8, and then each of those answers will be divisible by 3 and by 8.You can then multiply those numbers by 3 and/or 8, which will also be divisible by 3 and 8, and on and on....24 and any multiples, plus others...
The least number which can be divisible by each of the numbers is called least common multiple (LCM). As we know, 24=23x3 180=22x32x5 hence LCM of 24 and 180 is 23x32x5 = 360
1,2,3,4,6,8,12,24
1,2,3,4,6,8,12, and the number itself 24 :)
24, and any multiple of 24 would be divisible by both 3 and 8.
24 is divisible by all of them. But only 2,3,4,6 & 8 will return whole numbers.
24
Numbers divisible by 24 are those that can be divided by 24 without leaving a remainder. Some examples of numbers divisible by 24 include 24, 48, 72, 96, 120, and so on. This is because 24 is a multiple of 1, 2, 3, 4, 6, 8, 12, and itself, so any number that is a multiple of 24 will also be divisible by these factors.
Even numbers are divisible by 2. Even numbers that are divisible by 3 must be divisible by 2 and by 3, so they have to be divisible by 2 x 3.6, 12, 18, 24 …
Yes.