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Numbers that are divisible by both 3 and 8 must be divisible by their least common multiple, which is 24. Therefore, any number that is a multiple of 24 will be divisible by both 3 and 8. Examples of such numbers include 24, 48, 72, 96, and so on.

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Related Questions

How many numbers between 1 and 1000 are divisible by 3 and 8?

There are 41 numbers between 1 and 1,000 that are divisible by 3 and 8?


Numbers divisible by 3 and 8?

24, and any multiple of 24 would be divisible by both 3 and 8.


What numbers are divisible by 3 6 but is not divisible by 8?

36 is divisible by itself but not 8 36/36=1 36/8=4.5


What is the divisbility rule for 24?

Apply for the rules of 3 and 8. Numbers are divisible by 24 only if they are divisible by both 3 and 8.


Is a number always divisible by 4 if the sum of the digits is 8?

No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9


Is 11 divisible by 8 and 3?

11 is divisible by no whole numbers except 1 and 11.


Is the sum of three consecutive whole numbers divisible by three?

5+2+1=8 and 8 is not divisible by 3.


Why is that when a number is divisible by 2 and divisible by3 it is also by six how are they related why does this pattern not work for 2 4and 8?

Numbers divisible by 6 will have at least one 2 and one 3 as prime factors because 2 x 3 = 6. The same is true for 2, 4 and 8. Numbers divisible by 4 are also divisible by 2. Numbers divisible by 8 are also divisible by 4 and 2.


All numbers divisible by 8 and 12 are also divisible by?

All numbers that are divisible by 8 and 12 would also be divisible by 4.


Set all Prime numbers divisible by 3?

Prime numbers are only divisible by 1 and themselves. Since 3 is not a prime number, any prime number divisible by 3 does not exist. Therefore, the set of prime numbers divisible by 3 is an empty set.


What are the divisibility rules for 1 2 3 4 5 6 9 and 10?

All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.


Is 1428 divisible by 3?

yes 1428/3 = 476 if you add numbers up and you can divide sum by 3 then it is divisible by 3 1+4+2+8 = 15 which is divisible by 3