Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
24 + 25 + 26 = 75
The numbers are 23, 24 and 25.
The integers are are 41, 42 and 43.
201
The average of three numbers which sum to 66 is 66/3 = 22. If 22 is the sum of three consecutive integers, then those three integers are 21,22,23. Kermit Rose
66
Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
They are are 62, 63 and 64.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The sum of even integers cannot end with 9. why not
4 and 5
73,74,75
The integers are 16, 17 and 18.