The numbers are 21, 22 and 23.
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Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
24 + 25 + 26 = 75
The numbers are 23, 24 and 25.
The integers are are 41, 42 and 43.