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Those are both 'complex' numbers. Together, they are a pair of complex conjugates.

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Q: What are imaginary numbers of the form a bi and a-bi?
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Can a complex number be imaginary?

Yes, imaginary numbers are a subset of complex numbers.


What are the characteristics of a complex number?

A complex number must have a real and imaginary part. It can be in the form: a + bi i is an imaginary number and a and b are real numbers


How do you write complex numbers in the form a plus bi?

A complex number comes in two parts: a real part and an imaginary part. If the value of the real part is a and the value of the imaginary part is b, the number is written as a + bi.


What is the standard form of complex numbers?

a + bi. a & b are both real numbers. the number i is the imaginary unit equal to the positive square root of -1.


Fomular for complex numbers?

A complex number is a number with a real part and an imaginary part. It is written in the form a+bi. a is the real part & bi is the imaginary part. Recall that i = square root of -1. An example would be 2+3i.


Is Every complex number is a pure imaginary number?

No. All Complex Numbers are of the form a + bi where a and b are Real Numbers and i is the square root of -1. So only ones where a = 0 are pure Imaginary Numbers.


The set of complex numbers contains only numbers of the form a plus bi where a and b are positive numbers and you is the imaginary unit?

Not exactly. The numbers (a & b) can be any real number (positive or negative). It is the letter i, which represents the imaginary unit sqrt(-1).False


What are considered complex numbers?

A complex number is any number that can be represented in the form of a+bi, the real numbers are a and b, the imaginary number is i. Complex numbers are used in scientific and engineering fields.


How do you tell a real number?

It has no imaginary part. A complex number is of the form a + bi where a and b are real numbers, and i = √-1. A real number has b = 0.


How do you multiply imaginary numbers?

First, let's make sure we are not confusing imaginary numbers with complex numbers. Imaginary (sometimes called "pure imaginary" for clarity) numbers are numbers of the form ai, where a is a real number and i is the principal square root of -1. To multiply two imaginary numbers ai and bi, start by pretending that i is a variable (like x). So ai x bi = abi2. But since i is the square root of -1, i2=-1. So abi2=-ab. For example, 6i x 7i =-42. 5i x 2i =-10. (-5i) x 2i =-(-10)= 10. Complex numbers are numbers of the form a+bi, where a and b are real numbers. a is the real part, bi is the imaginary part. To multiply two complex numbers, again, just treat i as if it were a variable and then in the final answer, substitute -1 wherever you see i2. Hence (a+bi)(c+di) = ac + adi + bci + dbi2 which simplifies to ac-db + (ad+bc)i. For example: (2+3i)(4+5i) = 8 + 10i +12i + 15i2= 8 + 10i + 12i - 15 = -7 + 22i


How do you solve x squared plus 9 equals to zero?

The answer is x = 3i and x = -3i. {Where i= √(-1)}An expression in the form a2 - b2 can be factored into (a - b)(a + b), but you have a2 + b2 so this factors into (a - bi)(a + bi). Check by multiplying the binomials: a2 + abi - abi - (bi)2 the [abi]'s cancel, and i2 = -1, so you have a2 + abi - abi - -b2 which is a2 + b2, so it checks out. In this case, a is x and b is 3.


What is the Multiplicative inverse formula of complex numbers?

So if you have a number z = a + bi. Then how to find 1 divided by z. The way to figure this is to get the denominator as a pure real number. Multiplying the numerator and the denominator by the complex conjugate {a - bi} will result in a pure real denominator.(a - bi)(a + bi) = a² + abi - abi - (bi)² = a² + b². So the multiplicative inverse is(a - bi)/(a² + b²)