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Assuming the two points are (-4,-7) and (3,2) the equation for the slope would be (3-(-4))/(2-(-7)) which equals 7/9. If we use y=mx+b and the point (3,2) you get 2=(7/9)*3+b which simplifies to 2=2 1/3+b then by subtracting 2 1/3 from both sides you are left with b= -1/3. Thus the equation is y=7/9x-1/3.

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Q: What are pointslope equations of the line going through -4 and -7 and 3 and 2?
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