Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
The general equation of a line isy = mx + cIf the gradient is 3 then m = 3 so thaty = 3x + cSince the point (4,1) lies on this line, these coordinates must satisfy the equation.So 1 = 3*4 + cie c = -11Therefore, the equation is y = 3x - 11
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
It is an equation of a straight line.
Well, honey, if you're looking for a function that passes through the points (2, 15) and (3, 26), you're talking about a linear function. The slope of this function would be 11 (rise of 11 over run of 1), so the equation would be y = 11x + b. To find the y-intercept, plug in one of the points, let's say (2, 15), and solve for b. So, the function that passes through those points is y = 11x + 4.
it should actually look like this- 5x - y = 11 sorry
It is: y = 2x+11
The equation of a parallel line is of the form 2x - y = c for some c. (-3, -11) is on this lime so 2*(-3) - (-11) = c -6 + 11 = c so that c = 5 and therefore, the equation is 2x - y = 5
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
If you mean: 2x+3y = 6 then it is 2x+3y = 11
Y=_10.35x+126.125
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11
The general equation of a line isy = mx + cIf the gradient is 3 then m = 3 so thaty = 3x + cSince the point (4,1) lies on this line, these coordinates must satisfy the equation.So 1 = 3*4 + cie c = -11Therefore, the equation is y = 3x - 11
y+7=-4 the answer to the problem is y=-11
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
3x + y = 4 y = -3x + 4 (the slope is -3) The line that passes through the point (-3, -2) has a slope of -3, since it is parallel to the line with equation 3x + y = 4 (parallel lines have equal slopes). Using the slpoe -3 and the point (-3, -2) we find the equation of the required line such as (y - -2) = -3(x - -3) y + 2 = -3x - 9 y = -3x -11 3x + y = -11
Points: (4, 5) and (-3, -1) Slope: 6/7 Equation: 7y = 6x+11
It is: y-1 = 2(x--5) so: y = 2x+11