n-1, n and n+1 where n is an integer.
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
3 x 4 x 5 = 60 The three consecutive numbers are 3, 4, and 5.
The three consecutive odd prime numbers are 3, 5, and 7.
There is no set of three consecutive numbers totaling 170.
Yes, the sum of any three consecutive counting numbers has a factor of 3.
the sum of three consecutive numbers is 216. What are the three numbers?
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
3, 5 and 7 are consecutive odd prime numbers.
The least of the three numbers is 199.
To find three consecutive numbers that multiply to 60, you can start by estimating the cube root of 60, which is about 3.9. The three consecutive integers around this value are 3, 4, and 5. Multiplying these together: (3 \times 4 \times 5 = 60). Thus, the three consecutive numbers are 3, 4, and 5.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
Yes, three consecutive numbers can be divided by 3, but only one of them will be divisible by 3. In any set of three consecutive integers, one of the numbers will be a multiple of 3, while the other two will not be. For example, in the set (4, 5, 6), the number 6 is divisible by 3.