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It is likely that the centre is (0, 5) or (0, -5).

Q: What are the coordinates of the center of the circle described by the equation x2 (y 5)2 16?

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Center of circle: (6, 8) Radius of circle: 3

To determine the center and radius of a circle described by an equation in the form "(x-h)^2 + (y-k)^2 = r^2", we need to rewrite the given equation in that form. The equation (x-7)^2 + (y-6)^2 = 2100 is already in that form. Therefore, the center of the circle is at the point (7, 6) and the radius is the square root of 2100.

I think it is center: (-4, 3) ; radius: 2 Apex:)

An ellipse is described as [ (x/A)2 + (y/B)2 = C2 ] If [ A=B ] then the ellipse is a circle.

depends on the equation.

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The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius

Center of circle: (6, 8) Radius of circle: 3

There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.

The answer depends on what information is available and in what form.The simplest solution is to write the equation of the circle in the following form:(x - a)^2 + (y - b)^2 = r^2Hiving done that, the coordinates of the centre are (a, b), and the circle's radius is r.

Equation of a circle is given by: (x-a)2 + (y-b)2 = r2 Here a & b are the coordinates of the center. So, a = -3 & b = 6. And r = 10. Thus, the equation formed is (x+3)2+(y-6)2 = 102

To determine the center and radius of a circle described by an equation in the form "(x-h)^2 + (y-k)^2 = r^2", we need to rewrite the given equation in that form. The equation (x-7)^2 + (y-6)^2 = 2100 is already in that form. Therefore, the center of the circle is at the point (7, 6) and the radius is the square root of 2100.

I think it is center: (-4, 3) ; radius: 2 Apex:)

In the algebraic equation for a circle. (x - g)^2 + (y - h)^2 = r^2 'g' & 'h' are the centre of rotation.

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2

An ellipse is described as [ (x/A)2 + (y/B)2 = C2 ] If [ A=B ] then the ellipse is a circle.

depends on the equation.