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What else can I help you with?
What is the general form for a line equation?
General form for a line equation is: y=mx+b.
What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?
9
How do you find the variable in fraction equation?
It depends on the form of the equation.
What general equation represents the slope intercept form of a line?
The general equation is y = mx + c. m is the slope of the straight line. c is the y intercept. This is readily obtained by putting x = 0 then the general equation simplifies to y = c.
What is the formula to find the circumference of a circle when the diameter is known?
It is NOT a formula but an EQUATION . The answer is C = pi*d This equation has been known for thousands of years. It can also be in the form of C = 2 pi r NB 2r = d Also A = pi r^(2) for the area of a circle.
What is a general form of the equation of a circle?
yes
What is the general form of the equation of a circle with center a (ab) and the radius of length m?
The general form of the equation of a circle with center at the point ( (a, b) ) and a radius of length ( m ) is given by the equation ( (x - a)^2 + (y - b)^2 = m^2 ). Here, ( (x, y) ) represents any point on the circle. This equation expresses that the distance from any point on the circle to the center ( (a, b) ) is equal to the radius ( m ).
What is the general form for a line equation?
General form for a line equation is: y=mx+b.
What is the general form of the equation of a circle with center at (a b) and radius of length m?
It is: (x-a)^2 +(y-b)^2 = m squared
The equation below describes a circle. What are the coordinates of the center of the circle (x - 6)2 plus (y plus 5)2 152?
The equation of the circle is given by ((x - 6)^2 + (y + 5)^2 = 152). The general form of a circle's equation is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. From the equation, the coordinates of the center of the circle are ((6, -5)).
What is the general form of the equation of a circle with its center at (-2 1) and passing through (-4 1)?
It is (x + 2)^2 + (y - 1)^2 = 4
How do you find the discriminant of a equation?
The general form of a quadratic equation is ax2 + bx + c = 0 where a is not zero, a, b and c are constants. The discriminant is b2 - 4ac
How do you draw a flow chart to find the equation of a circle passing through three given points?
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
Which number in the standard equation for a circle centered at the origin should one increase to make the circle larger?
You should increase the radius in the standard equation of a circle centered at the origin. The general form is ( x^2 + y^2 = r^2 ), where ( r ) is the radius. By increasing ( r ), you extend the distance from the center to any point on the circle, making it larger.
What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?
9
Find the equation of a circle with center -2 and -4 and radius 3?
The equation for a circle is generally written in the form (x+a)^2+(y+b)^2 = r^2Remember, for the centres for the x and y value, they go in the opposite direction of the rule.So:if the centre is (-2,-4), the equation of the circle is (x+2)^2+(y+4)^2=9
How is the Pythagorean theorem used to develop the equation of a circle in standard form?
The Pythagorean theorem is used to develop the equation of the circle. This is because a triangle can be drawn with the radius and any other adjacent line in the circle.
