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What is the equation of a circle with radius 10 and center -3 and 6?
Wiki User
∙ 12y ago
Equation of a circle is given by:
(x-a)2 + (y-b)2 = r2
Here a & b are the coordinates of the center.
So, a = -3 & b = 6. And r = 10.
Thus, the equation formed is (x+3)2+(y-6)2 = 102
Wiki User
∙ 12y ago
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What is the equation of a circle whose center is at the origin and whose radius is 10?
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
What is the equation for a circle with a center of -4 0 and a radius of 10?
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Endpoints of diameter: (-10, -2) and (4, 6)Midpoint which is the center of the circle: (-3, 2)Radius of the circle: square root of 65Equation of the circle: (x+3)^2 +(y-2)^2 = 65
What is the center and radius of a circle with an equation of x squared plus y squared - 10x plus 6y equals 47?
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What is the radius of a circle with a circumference of 10 units?
The radius is about 1.6 units.
What is the equation of a circle whose center is at the origin and whose radius is 10?
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
Find the center and radius of the circle with this equation X2 plus Y2 minus 6X plus 2Y equals 0?
The centre is (3,-1) and the radius is sqrt(10).
What is the equation for a circle with a center of -4 0 and a radius of 10?
The general formula: (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius. So the required equation of the circle is: (x - -4)^2 + (y - 0)^2 = 10^2 (x + 4)^2 + y ^2 = 100
What are the center and radius of the circle described by the equation (x-7)2 (y 6)2100?
To determine the center and radius of a circle described by an equation in the form "(x-h)^2 + (y-k)^2 = r^2", we need to rewrite the given equation in that form. The equation (x-7)^2 + (y-6)^2 = 2100 is already in that form. Therefore, the center of the circle is at the point (7, 6) and the radius is the square root of 2100.
What is the equation of a circle centered at the origin with a radius of 10?
x² + y² = 100.
What is the circle's equation with a length of it's radius is 10?
If the centre of the circle is at the point (a, b), the equation is: (x - a)2+ (y - b)2= 100.
If the radius of a circle is 10 inches what is the diameter?
The radius is half the diameter. The diameter is twice the radius. If the radius is 10 inches, the diameter is twice that, or 20 inches. The radius is any straight line that connects a point on the circle with it's center. The diameter is a line segment that connects two points on a cirle throught the center of the circle.Answer:Let r be the radius of the circle and d be the diameter of the circle. We know that the diameter = 2 * radius of the circle. Given the radius r = 10 inches. Diameter d = 2 * 10 Diameter = 20 inches.
Center and the radius of the circle x2 plus 4x plus y2 - 6x 10?
The radius will depend on the plus or minus value of 10 or whether or not it needs a plus sign but the center of the circle is at (-2, 3)
What is the radius of the circle if the center of the circle is C(-35) and the point P(511) is on the circle?
If you mean (-3, 5) and (5, 11) then using the distance formula the radius of the circle is 10 units
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The circumference of a circle can be found using the equation c=2πr. For example, if a circle has a radius of 10, its circumference is 20π, or 62.832.
Which equation can be used to find the circumference of a circle with a radius that measures 10 feet?
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Give the equation for a circle center at 2 and center 8 and radius the square the root of 10?
Since the 2 would be the x in the center coordinate (x,y) and 8 would be the y respectively they would fit into the following equation for a circle as follows: (x-h)^2 + (y-k)^2 = r^2 (x-2)^2 + (y-8)^2 = (square root of 10)^2 Remember that the 2 for the x would become negative because the equation states that the h value becomes negative....same for the y value as well. The final equation after squaring the square root of 10 would be: (x-2)^2 + (y-8)^2 = 10 This would be the final equation of the circle with center (2,8) and radius of root 10. Hope this helped! :) I'd guess that your question involves a circle centered at the cartesian coordinate (2,8): Your standard equation goes as follows: (x-2)2+(y-2)2=10 x2+y2-4x-16y+58=0 for circle with centre at(2,8) and radius the squareroot of 10. (x-2)^2 + (y-8)^2 = 10
