Anything. No area is specified, so the dimensions are w*(4w+5) This equation lacks any value to define w.
length times width
8X36
If those are the dimensions of a rectangle, simply multiply length times width.
That would be 3 x 9 inches.
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
length times width
They are 6 and 12
Without the dimensions, we won't be able to tell. The area of a rectangle is the length times the width. If those dimensions are in inches, the area will be in square inches.
18.4cm by 22.4cm
The dimensions work out as: length = 30 times the square root of 5 breadth = 40 times the square root of 5 check: (30 times sq rt of 5)*(40 times sq rt of 5) = 6000 square units
Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet
Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63
8X36
If those are the dimensions of a rectangle, simply multiply length times width.
That would be 3 x 9 inches.
It is the area of the rectangle which is length times width
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.