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What are the dimensions of a rectangle when one side is 3 cm longer than the other side and its area is twice its perimeter?
Wiki User
∙ 13y ago
Let one side be (x+3) and the other side be x:
area = 2(perimeter)
(x+3)*x = 2*2(x+3+x)
x2+3x = 4x+12+4x
x2+3x-8x-12 = 0
x2-5x-12 = 0
Solving the above equation using the quadratic equation formula and a calculator works out to 2 d.p. as:
x = -1.77 or x = 6.77 it must be the latter as dimensions can't be negative.
Therefore the dimensions are 6.77 cm and 9.77 cm
Wiki User
∙ 13y ago
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