Your question cannot be answered. An area of 14 acres is equivalent to 609,840 square feet, but a rectangle with that area could be 609,840 feet by 1 foot, or it could be 1089 feet by 560 feet, or many other possible dimensions, each of which would have a different perimeter.
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
The dimensions of the rectangle are 2 units and 15 units
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
The rectangle has dimensions of [ 12 x 3 ].
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
The dimensions of the rectangle are 2 units and 15 units
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
That depends on the dimensions !... A 1 x 18 rectangle has a perimeter of 38 ! A 2 x 9 rectangle has a perimeter of 22 ! A 3 x 6 rectangle has a perimeter of 18 !
21 x 2 has greatest perimeter
me
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
To determine the perimeter of a rectangle, we need both the length and width. The area of the rectangle is given as 20 cm², but without the specific dimensions, we cannot calculate the perimeter directly. For example, if the rectangle has a length of 5 cm and a width of 4 cm, the perimeter would be 2(5 + 4) = 18 cm. Thus, the perimeter varies depending on the rectangle's dimensions.
If they are the dimensions of a rectangle then the perimeter is: 2*(26+16) = 84
54
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.