A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m.
Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
960m
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
The width of the rectangle is 8. 48/6 = 8
It would be 15 inches long.
Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in
28 inches
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
7 x 17
Width = 48/8 = 6 Perimeter = (length + width) x 2 = 14 x 2 = 28.
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
112 inches
Well, L=6 and W=18If you do the math you get (6*2)+(18*2)=12+36=48Your final answer 48 yd. The perimeter is 48 yd.
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
2*24
The width of the rectangle is 8. 48/6 = 8
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.