A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m.
Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
The width of the rectangle is 8. 48/6 = 8
It would be 15 inches long.
Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in
28 inches
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
7 x 17
Width = 48/8 = 6 Perimeter = (length + width) x 2 = 14 x 2 = 28.
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
112 inches
Well, L=6 and W=18If you do the math you get (6*2)+(18*2)=12+36=48Your final answer 48 yd. The perimeter is 48 yd.
The perimeter of a rectangle is calculated by adding all four sides together. In this case, the length of the rectangle is 18 cm and the width is 6 cm. To find the perimeter, you would add 18 cm (length) + 18 cm (length) + 6 cm (width) + 6 cm (width) = 48 cm. Therefore, the perimeter of the rectangle is 48 cm.
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
2*24
The width of the rectangle is 8. 48/6 = 8