This is not answerable in this form because it could have sides of 7,7,1, and 1, or it could have sides of 6,6,2, and 2, among others. More information is needed.
If they are the dimensions of a rectangle then the perimeter is: 2*(26+16) = 84
Perimeter = (2*pi*5*1/2)+10+16+16 = 57.70796327 or 58 feet
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.
The dimensions are: 3.5 cm and 4.5 cm Check: perimeter = 3.5+4.5+3.5+4.5 = 16 cm and area = 3.5*4.5 = 15.75 cm2
If they are the dimensions of a rectangle then the perimeter is: 2*(26+16) = 84
Perimeter = (2*pi*5*1/2)+10+16+16 = 57.70796327 or 58 feet
It is 9+16+9+16 = 50 feet
A 6 by 2 feet rectangle
The perimeter is 18 feet.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
A rectangle has 2 pairs of equal sides. perimeter is the sum of the lengths of all sides: Perimeter = 12 + 12 + 16 + 16 = 56 Ft Area = 12 x 16 = 192 Ft2
If those are the dimensions of a rectangle then its perimeter is 2*(5+3)=16 yards
Ok, an important part of this is that shapes can be categorized into multiple groups. It goes something like this in this case: Quadrilateral V Rectangle V Square When dealing with shapes, regular polygons always have less perimeter than irregular for the same area. Here, a square would have a perimeter of 16, with 4x4 dimensions; the next closest rectangle would have a perimeter of 20, with dimensions of 8x2; the last rectangle you could make would have a perimeter of 34, with dimensions of 16x1.
4 x 4 1 x 16
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.