The rectangle cannot have an area of 100 feet, since that is a measure of distance and not area. Assume, therefore, that the area is 100 SQUARE feet.
Suppose the rectagle has length L and width W
then 2(L + W) = 401
and L*W = 100
So L = 100/W
Then 2(100/W + W) = 401
Multiply by W: 2(100 + W2) = 401W
or 2W2 - 401W + 200 = 0
or (2W - 1)(W-200) = 0
So W = 0.5 ft or W = 200 ft which imply that L = 200 ft or 0.5 ft respectively.
So, the dimensions are 200 ft by 0.5 ft (or 6 inches).
Possibly 2 feet by 12 feet
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
5
4 feet
2
It could be a rectangle with dimensions of 6 feet by 3 feet.
Possibly 2 feet by 12 feet
Your question cannot be answered. An area of 14 acres is equivalent to 609,840 square feet, but a rectangle with that area could be 609,840 feet by 1 foot, or it could be 1089 feet by 560 feet, or many other possible dimensions, each of which would have a different perimeter.
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
If the given dimensions are that of a rectangle then perimeter is: 34 feet
5
4 feet
4 feet
2
A 6 by 2 feet rectangle
The perimeter is 18 feet.
Write two simultaneous equations and solve them. One for the perimeter, one for the area.