For 2 it's any even number.For 5 it's if the number ends in 5 or 0.For 10 it's if the number ends with a zero. That's basically it.
1000 times 1000 is divisible by 2, 4, 5, 8 and 10.
If the rules for 2 and 3 work, the number is divisibale by 5.
Do the division, if there is no remainder, it is divisible. Seriously, many of the "divisibility rules" that have been discovered become more complicated than doing the actual division. For practical purposes, just learn the divisibility rules for a few simple cases (divisibility rules by 2, 4, 8, 5, 10, 3, 9, 7, 11, and 13), and for all other cases, just do the division.
Yes, you can tell using the divisibility rules. The answers are yes for all but 5 and 10.
26
1000 times 1000 is divisible by 2, 4, 5, 8 and 10.
If the rules for 2 and 3 work, the number is divisibale by 5.
3 and 9. And they divide into 123456789 whether or not you use divisibility rules!
Do the division, if there is no remainder, it is divisible. Seriously, many of the "divisibility rules" that have been discovered become more complicated than doing the actual division. For practical purposes, just learn the divisibility rules for a few simple cases (divisibility rules by 2, 4, 8, 5, 10, 3, 9, 7, 11, and 13), and for all other cases, just do the division.
Yes, you can tell using the divisibility rules. The answers are yes for all but 5 and 10.
26
No.
the divisibility rule for 2 is: The number is even;the last digit ends with a 2,4,6,8,10, etc.The divisibility rule fir 3 is: The sum of the number is divisible by 3The divisibility rule for 4 is: The last two digits are divisible by 4The divisibility rule for 5 is: The number ends with a 5 or 0The divisibility rule for 6 is: The sum CAN be divisible by 2 and or 3The divisibility rule for 9 is: The sum of the number is divisible by 9The divisibility rule for 10 is : The number ends with a 0
Those for 1, 2, 4, 5 and 8.
You should learn to make your question clear to someone who doesn't know what you are doing. And why 895 of all numbers? If I guess what you want correctly, first you should factorize 895 = 5 * 179.. a number is divisible by 2 * 5 * 179 if and only if it is divisible by 10 and 179 separately, because 10 and 179 have no common factor. You should know the divisibility rules for 10 already. For 179, there isn't a simple test.
Divide by two and five. 1, 2, 4, 5, 10, 20
It is divisible by 3 and 9 but not the others.