If its base diagonals are 8 and 6 then by using Pythagoras it will have 4 equal lengths of 5 cm.
Check: 0.5*8*6*1/3*5 = 40 cubic cm
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
Volume of pyramid: 1/3*8squared*3 = 64 cubic cm
Since the diagonals of a rhombus are perpendicular between them, then in one forth part of the rhombus they form a right triangle where hypotenuse is the side of the rhombus, the base and the height are one half part of its diagonals. Let's take a look at this right triangle.The base and the height lengths could be congruent if and only if the angles opposite to them have a measure of 45⁰, which is impossible to a rhombus because these angles have different measures as they are one half of the two adjacent angles of the rhombus (the diagonals of a rhombus bisect the vertex angles from where they are drawn), which also have different measures (their sum is 180⁰ ).Therefore, the diagonals of a rhombus are not congruent as their one half are not (the diagonals of a rhombus bisect each other).
The height of the triangular face of a pyramid is called the slant height.
To find the perpendicular height of a square pyramid, first compute for the volume of the pyramid. Then divide the volume by the area of the base to find pyramid's height.
Any formula for the height of a rhombus will depend on the information that you do have. Without that, all that can be said is that, if the sides of the rhombus are x units, then 0 < h < x where the height is h units. If h = 0 then the rhombus degenerates into a flat line, while at h = x it becomes a square.
integer in 5'6 in height
It is its vertical perpendicular height
A pyramid is a generic term used to describe a polyhedron with a polygonal base and triangles rising from that base to meet at an apex. The polygonal base can have any number, n, of sides, provided that n>2. There is, therefore, no information about the number of lateral faces in the pyramid. Also, the surface area of a pyramid depends on its height and there is no information whatsoever about its height. It is, therefore, impossible to answer such an underspecified question.
You cannot. The lengths and widths are not sufficient information to determine the height.
1/3(b*h) b means the base of the pyramid h means the height of height of the pyramid. The height is not to be confused with the lateral height (Which is the slanted height.) The height is found by drawing a segment from the vertex (or apex) of the pyramid to the center of the base.
slant height of the pyramid Louvre in Paris=28 meters