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If its base diagonals are 8 and 6 then by using Pythagoras it will have 4 equal lengths of 5 cm.

Check: 0.5*8*6*1/3*5 = 40 cubic cm

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Q: What are the integer base lengths of a rhombus based pyramid whose height is 5 cm with a volume of 40 cubic cm?
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What is the slant height of a pyramid that has all sides as equilateral triangles with sides of length of 9 cm and the surface area of the pyramid is 140.4 square cm?

The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.


What is the volume of a pyramid with a height of 3 centimeters and a square base with side lengths that measure 8 centimeters?

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Prove that a rhombus has congruent diagonals?

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What is the height of the triangular faces of a pyramid called?

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Any formula for the height of a rhombus will depend on the information that you do have. Without that, all that can be said is that, if the sides of the rhombus are x units, then 0 < h < x where the height is h units. If h = 0 then the rhombus degenerates into a flat line, while at h = x it becomes a square.


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