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If you multiply the lengths of the two diagonals, and divide by 2, you get the area of a rhombus. How does this work:

Call the diagonals A & B for clarity. Diagonal A will split the rhombus into 2 congruent triangles. Looking at one of these triangles, its base is the diagonal A, and its height is 1/2 of diagonal B. So the area of one of the triangles is (1/2)*base*height = (1/2)*A*(B/2) = A*B/4. The other triangle has the same area, so the two areas together make up the whole rhombus = 2*(A*B/4) = A*B/2.

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Q: Where did the area of a rhombus come from?
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What is the area of a 3cm rhombus?

The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).


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What is the value of rhombus if it is 3x 12?

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