95, is the two digits after the last digit of the multiple of 5's.
are the last TWO digits of 5347. 5, 3, 4, and 7 are all digits of the number 5347.
Assuming that the last two digits are indicators of precision, there are 5 significant digits.
25
25
Since there are two multiples of 5, and plenty of even numbers, the last two digits are 00.
i think it is 25
5 only has one digit or you mean 05 not 5
if repeating is allowed... 36 (6x6, for the last two digits) If not, 6 (3x2, last two digits)
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
Reqd no. is 9 -digits.. available digits are 1 2 3 4 5.. Numbers which are divisible by 4 can be determined by the last two digits.. from the given combinations,, the numbers div by 4 are 12, 24, 32, 44, 52 so.. the number's last two digits can be any of the above 5. Hence, we have to calculate the combinations for the first 7 digits.. Ans: (5C1)^7 * 5 ie 5^8 = 390625
if the last two digits are lesser than 50 (e.g. 8634), you round down by making the last two digits 0 (in this case, 8600).If the last two digits are greater than 50 (e.g. 8662), you round up by adding 1 to the hundreds and making the last two digits 0 (in this case, 8700).If the last two digits are exactly 50, you can round up or down, your choice.