0
How many 9 digit numbers which are divisible by 4 can be formed by using the digits 1 to 5 if repetition of digits is allowed?
Reqd no. is 9 -digits.. available digits are 1 2 3 4 5.. Numbers which are divisible by 4 can be determined by the last two digits.. from the given combinations,, the numbers div by 4 are 12, 24, 32, 44, 52
so.. the number's last two digits can be any of the above 5.
Hence, we have to calculate the combinations for the first 7 digits..
Ans: (5C1)^7 * 5
ie 5^8 = 390625
What else can I help you with?
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?
125
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
How many 4 digit numbers can be made to give the sum of 6?
If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.
How many 13 digit no are possible by using the digits 12345 which are divisible by 4 if repetition of digits is allowed?
5 ^12
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3 digit number can be made using the digits 2 4 7 9?
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
How many 2-digit numbers can be produce using the digits 123456789 if repetition is not allowed?
-123456787
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?
125
How man 7 digit combinations can be made using numbers 0 through 9?
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?
290
