Let one side be x+5 and the other side be x:
1/2*(sum of both parallel sides)*height = area
1/2*(x+5+x)*9 = 94.5 sq cm
Mutiply both sides by 2:
(x+5+x)*9 = 189
Divide both sides by 9
x+5+x = 21
2x = 21-5
2x = 16
x = 8
Therefore the lengths are 13 cm and 8 cm
Check: 1/2*(13+8)*9 = 94.5 sq cm
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.
The information given describes a square and not a trapezium. Area of the square = 3*3 = 9 square cm
Volume = 1/2*(a+b)*h*l where a and b are the lengths of the parallel sides of the trapezium, h is the height of the trapezium, and l is the length of the prism.
Atrapezoidor trapezium is a quadrilateral with two parallel sides. These two sides are called the bases. Find the average of the lengths of the bases andmultiplyby the perpendicular distance between the parallel sides (the height).bases have lengths a and b, height is h: A = h(a+b)/2
If the lengths of the two parallel sides are a and b, and the height of the trapezium (the distance between them) is h, then area_of_trapezium = 1/2 (a + b) h that is half of the sum of the lengths of the two parallel sides multiplied by the distance between them.
Which side lengths? To calculate the parallel sides, you need the height of the trapezium and one of the sides, and you substitute them into the formula: h(a + b)/2, where h = height, a and b are the parallel side lengths. If you want to find the sides that are not parallel, you need the parallel sides, as well as the height of the trapezium. Then, by using Pythagoras theorem, with the side length the hypotenuse, you can find their lengths.
A trapezium has a pair of parallel sides of different lengths so in order to find its 2nd parallel side the information given must include its height.
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.
The information given describes a square and not a trapezium. Area of the square = 3*3 = 9 square cm
Volume = 1/2*(a+b)*h*l where a and b are the lengths of the parallel sides of the trapezium, h is the height of the trapezium, and l is the length of the prism.
5x3 + ½*(7-5)*3 = 15+3 = 18 cm²
Atrapezoidor trapezium is a quadrilateral with two parallel sides. These two sides are called the bases. Find the average of the lengths of the bases andmultiplyby the perpendicular distance between the parallel sides (the height).bases have lengths a and b, height is h: A = h(a+b)/2
If the lengths of the two parallel sides are a and b, and the height of the trapezium (the distance between them) is h, then area_of_trapezium = 1/2 (a + b) h that is half of the sum of the lengths of the two parallel sides multiplied by the distance between them.
Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
Call the two parallel sides a and b and find their average, a+b divided by 2. This is the average of the horizontal lengths. Now multiply this by height, the height, and you have the area!It's easy!
If the lengths of the parallel sides are x and y units, and the height is h units, then the area = 1/2*(x + y)*h square units.