Let one side be x+5 and the other side be x:
1/2*(sum of both parallel sides)*height = area
1/2*(x+5+x)*9 = 94.5 sq cm
Mutiply both sides by 2:
(x+5+x)*9 = 189
Divide both sides by 9
x+5+x = 21
2x = 21-5
2x = 16
x = 8
Therefore the lengths are 13 cm and 8 cm
Check: 1/2*(13+8)*9 = 94.5 sq cm
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.
The information given describes a square and not a trapezium. Area of the square = 3*3 = 9 square cm
To work out the lengths of a trapezium, you can use the properties of its parallel sides (bases) and the height. If the lengths of the two bases are known, the area can be calculated using the formula ( \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h ), where ( b_1 ) and ( b_2 ) are the lengths of the bases and ( h ) is the height. Additionally, if the lengths of the non-parallel sides are known, you can apply the Pythagorean theorem to find the lengths of any missing sides if needed. For a more complex trapezium, trigonometric relationships or coordinate geometry may be used.
Volume = 1/2*(a+b)*h*l where a and b are the lengths of the parallel sides of the trapezium, h is the height of the trapezium, and l is the length of the prism.
The altitude of a trapezium (or trapezoid) is the perpendicular distance between its two parallel sides. It is the shortest distance between these sides and is essential for calculating the area of the trapezium using the formula: Area = (1/2) × (Base1 + Base2) × Height, where Base1 and Base2 are the lengths of the parallel sides.
Which side lengths? To calculate the parallel sides, you need the height of the trapezium and one of the sides, and you substitute them into the formula: h(a + b)/2, where h = height, a and b are the parallel side lengths. If you want to find the sides that are not parallel, you need the parallel sides, as well as the height of the trapezium. Then, by using Pythagoras theorem, with the side length the hypotenuse, you can find their lengths.
A trapezium has a pair of parallel sides of different lengths so in order to find its 2nd parallel side the information given must include its height.
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.
The information given describes a square and not a trapezium. Area of the square = 3*3 = 9 square cm
To work out the lengths of a trapezium, you can use the properties of its parallel sides (bases) and the height. If the lengths of the two bases are known, the area can be calculated using the formula ( \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h ), where ( b_1 ) and ( b_2 ) are the lengths of the bases and ( h ) is the height. Additionally, if the lengths of the non-parallel sides are known, you can apply the Pythagorean theorem to find the lengths of any missing sides if needed. For a more complex trapezium, trigonometric relationships or coordinate geometry may be used.
Oh, what a happy little question! To find the area of a trapezium, you can use the formula: 1/2 * (sum of parallel lengths) * height. So, for this trapezium with lengths of 5cm and 7cm, and a height of 3cm, the area would be 1/2 * (5 + 7) * 3 = 1/2 * 12 * 3 = 18 square centimeters. Just imagine that beautiful shape on your canvas!
Volume = 1/2*(a+b)*h*l where a and b are the lengths of the parallel sides of the trapezium, h is the height of the trapezium, and l is the length of the prism.
The altitude of a trapezium (or trapezoid) is the perpendicular distance between its two parallel sides. It is the shortest distance between these sides and is essential for calculating the area of the trapezium using the formula: Area = (1/2) × (Base1 + Base2) × Height, where Base1 and Base2 are the lengths of the parallel sides.
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
If the lengths of the two parallel sides are a and b, and the height of the trapezium (the distance between them) is h, then area_of_trapezium = 1/2 (a + b) h that is half of the sum of the lengths of the two parallel sides multiplied by the distance between them.
Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.
Atrapezoidor trapezium is a quadrilateral with two parallel sides. These two sides are called the bases. Find the average of the lengths of the bases andmultiplyby the perpendicular distance between the parallel sides (the height).bases have lengths a and b, height is h: A = h(a+b)/2