Oh, what a happy little question! To find the area of a trapezium, you can use the formula: 1/2 * (sum of parallel lengths) * height. So, for this trapezium with lengths of 5cm and 7cm, and a height of 3cm, the area would be 1/2 * (5 + 7) * 3 = 1/2 * 12 * 3 = 18 square centimeters. Just imagine that beautiful shape on your canvas!
None but if you mean area it is: Area measured in square units = 0.5*(sum of parallel sides)*height
The area of the trapezium cannot be 140 metres since the latter is a length, not an area. Suppose the area is 140 m2 = 1400000 cm2 Suppose the length of the second parallel side is x cm. Area of trapezium = 1/2*(sum of lengths of parallel sides*distance between them) ie 1400000 = 1/2*[(16+x)*10] 280000 = 16+x so x = 279984 cm = 2.79984 kilometres.
The formulae are quite similar; you multiply base x height, where the height is perpendicular to the base. In the case of a trapezium, you need to calculate the average of the two bases first.
The volume is the Area multiplied by thickness (if the thickness is constant). Area = 1/2 ((a+b)*h) a = the base length b = the top length h = the height (constant) t = the thickness (constant) Volume = Area*t Please note that a trapezium and a trapezoid are defined differently in England and the USA. In England the trapezium has the base and top parallel and the area calculation above is for that definition but the area calculation for a trapezoid is different. The volume will still be Area*t.
1/2 x (sum of bases) x height
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.
A trapezium has a pair of parallel sides of different lengths so in order to find its 2nd parallel side the information given must include its height.
The information given describes a square and not a trapezium. Area of the square = 3*3 = 9 square cm
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.
Call the two parallel sides a and b and find their average, a+b divided by 2. This is the average of the horizontal lengths. Now multiply this by height, the height, and you have the area!It's easy!
If the lengths of the parallel sides are x and y units, and the height is h units, then the area = 1/2*(x + y)*h square units.
If the lengths of the two parallel sides are a and b, and the height of the trapezium (the distance between them) is h, then area_of_trapezium = 1/2 (a + b) h that is half of the sum of the lengths of the two parallel sides multiplied by the distance between them.
Atrapezoidor trapezium is a quadrilateral with two parallel sides. These two sides are called the bases. Find the average of the lengths of the bases andmultiplyby the perpendicular distance between the parallel sides (the height).bases have lengths a and b, height is h: A = h(a+b)/2
Area = 1/2*(sum of the parallel sides)*height
Area of a trapezium = 0.5*(sum of parallel sides)*height
has two parallel sideshas four straight linesThe area of the trapezium is given by the following formula where a and b are the lengths of the parallel sides and h is the perpendicular distance between the parallel sides.