The odds of one die being any number is 1 in 1. The odds of any of the next seven dice being the same as the first die is 1 in 6. The odds of the last two being different than the first die is 5 in 6.
The dice are unrelated to each other, and it does not matter in what order they are thrown, so the odds of eight matching dice out of ten dice is (1 in 1)1 (1 in 6)7 (5 in 6)2, or 25 in 10,077,696.
The odds are 1 in 36 that you will roll a sum of 2 in a single roll of two fair dice.
To roll a three on any one dice, the odds are 1/6. To roll a three on any one of a pair of dice, the odds are 1/6 x 1/6 which is 1/36 or 1 in 36 chance.
The odds of rolling five of a kind with five dice is 1 in 1296. The first die is going to roll something, so the odds are 1 in 1. Each of the other dice have a probability of 1 in 6 of matching the first die, so the resultant probability is (1 in 1) times (1 in 6) to the fourth power.
1 in 6. Basically dice 1 can roll any number So the odds are that dice 2 has the same number as dice 1, or 1 in 6
Zero. If you roll five dice, you cannot get six 6s.
6
1 out of 6
No.
4/36 or 1/9
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
No. Each roll is independent of the previous roll (on a fair dice). The same is true for flipping a coin. Getting a six your first roll does not make you any more or less likely to roll a six the second time.
well u can not roll a 7 on a dice