answersLogoWhite

0


Best Answer

If: 3x-2y = 1 and 3x^2-2y^2+5 = 0

Then by rearranging: 3x = 2y+1 and y^2-2y-8 = 0

Solving the above quadratic equation: y = 4 or y = -2

Bu substitution points of intersection are: (3, 4) and (-1, -2)

User Avatar

Wiki User

9y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What are the points of intersection of 3x -2y equal 1 with 3 x squares - 2y squared plus 5 equals 0 on the Cartesian plane?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What are the points of intersection of 3x -2y -1 equals 0 with 3x squared -2y squared equals -5 on the Cartesian plane?

Points of intersection work out as: (3, 4) and (-1, -2)


What is x squared plus 25 times y squared equals 50?

It is the Cartesian equation of an ellipse.


What are the points of intersection of the line x -y equals 2 with x squared -4y squared equals 5?

The points of intersection are: (7/3, 1/3) and (3, 1)


What squared equals 2?

4


What is the point of intersection of the lines 6y equals -x -25 and 6x plus 20.5 -y equals 0?

It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.


Can 5077 be expressed as the sum of two perfect squares?

Yes. 6 squared+71 squared equals 5077


What are the points of intersection of the parabolas of y equals 4x squared -12x -3 and y equals x squared plus 11x plus 5 on the Cartesian plane?

The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)


Where are the points of intersection of the equations 4y squared -3x squared equals 1 and x -2y equals 1?

The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)


What are the points of intersection of the line 2x plus y equals 5 with x squared minus y squared equals 3 on the Cartesian plane showing work?

Improved Answer:-If: 2x+y = 5 and x^2 -y^2 = 3Then by rearranging: y = 5 -2x and -3x^2 -28+20x = 0Solving the above quadratic equation: x = 2 and x = 14/3By substitution points of intersection are: (2, 1) and (14/3, -13/3)


What is the point of intersection of the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?

They intersect at the point of: (-3/2, 11/4)


Would x equals 4 show a horizontal line?

No, in the Cartesian coordinate system it would show a vertical line whose intersection of the x-axis is 4.


What are points of intersection of the line 3x -y equals 5 with the curve of 2x squared plus y squared equals 129?

Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)