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What are the points of intersection of x - y equals 2 and x square - 4y square equals 5?
Wiki User
∙ 13y ago
Rearrange the first equation to y = 2-x and then substitute this into the second equation to form the quadratic equation:
-3y2+4y-1 = 0 and when solved y = 3 or y = 1/3
Points of intersection are: (3,1) and (2 and 1/3, 1/3)
Wiki User
∙ 13y ago
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What are the points of intersection of the line x -y equals 2 with x squared -4y squared equals 5?
The points of intersection are: (7/3, 1/3) and (3, 1)
What are the points of intersection of the line x -y equals 2 with the curve x squared - 4y squared equals 5?
If: x-y = 2 then x = 2+y If: x^2 -4y^2 = 5 then (2+y)^2 -4y^2 -5 = 0 Removing brackets: 4+4y+y^2 -4y^2 -5 = 0 Collecting like terms: 4y-3y^2 -1 = 0 Dividing all terms by -1: 3y^2 -4y+1 = 0 Factorizing the above: (3y-1)(y-1) = 0 meaning y = 1/3 or y = 1 Points of intersection by substitution are at: (7/3, 1/3) and (3, 1)
What are the points of intersection between the line x -y equals 2 and the curve x2 -4y2 equals 5?
Equations: x -y = 2 and x^2 -4y^2 = 5 By combining the equations into a single quadratic equation in terms of y and solving it: y = 1/3 or y = 1 By means of substitution the points of intersection are at: (7/3, 1/3) and (3, 1)
What is the answer for 7x-4y equals 217?
The answer comprises infinitely many points on a straight line.
How do you write 8x plus 4y equals 5?
8x plus 4y equals 5 is 8x + 4y = 5.
What are the points of intersection of the line x -y equals 2 with x squared -4y squared equals 5?
The points of intersection are: (7/3, 1/3) and (3, 1)
Where are the points of intersection of the equations 4y squared -3x squared equals 1 and x -2y equals 1?
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
What are the points of intersection of the line x -2 equals 2 with x2 -4y2 equals 5?
x - 2 = 2 → x = 4 → x² - 4y² = 5 → 4² - 4y² = 5 → 4y² = 16 - 5 → 4y² = 11 → y² = 11/4 → y = ± √(11/4) → The points of intersection of x - 2 = 2 with x² - 4y² = 5 are (4, -√(11/4)) ≈ 4, -1.658) and (4, √(11/4)) ≈ 4, 1.658)
What is the point of intersection of the equation 4y equals 5x with the line joining the points 13 17 and 19 23 on the Cartesian plane showing work?
Points of line: (13, 17) and (19, 23) Its slope: 1 Its equation: y = x+4 => y-x = 4 Multiply all terms by 4: 4y-4x = 16 Equation of: 4y = 5x => 4y-5x = 0 Subtacting equations: x = 16 By substitution point of intersection is at: (16, 20)
What are the points of intersection of the line x -y equals 2 with the curve x squared - 4y squared equals 5?
If: x-y = 2 then x = 2+y If: x^2 -4y^2 = 5 then (2+y)^2 -4y^2 -5 = 0 Removing brackets: 4+4y+y^2 -4y^2 -5 = 0 Collecting like terms: 4y-3y^2 -1 = 0 Dividing all terms by -1: 3y^2 -4y+1 = 0 Factorizing the above: (3y-1)(y-1) = 0 meaning y = 1/3 or y = 1 Points of intersection by substitution are at: (7/3, 1/3) and (3, 1)
What are the points of intersection between the line x -y equals 2 and the curve x2 -4y2 equals 5?
Equations: x -y = 2 and x^2 -4y^2 = 5 By combining the equations into a single quadratic equation in terms of y and solving it: y = 1/3 or y = 1 By means of substitution the points of intersection are at: (7/3, 1/3) and (3, 1)
Which pair of points lies on 4y-6x equals x-8?
(4,5) and (2,0)
What is the answer for 7x-4y equals 217?
The answer comprises infinitely many points on a straight line.
What are the points of intersection when the line x -y equals 2 crosses the curve x squared - 4y squared equals 5?
If: x -y = 2 then x^2 = y^2 +4y +4 If: x^2 -4y^2 = 5 then x^2 = 4y^2 +5 So: 4y^2 +5 = y^2 +4y +4 Transposing terms: 3y^2 -4y +1 = 0 Factorizing the above: (3y -1)(y -1) = 0 meaning y = 1/3 or y = 1 Substitution into the original linear equation intersections are at: (7/3, 1/3) and (3, 1)
How do you write 8x plus 4y equals 5?
8x plus 4y equals 5 is 8x + 4y = 5.
If 6x-8y equals 10 and 2x-4y equals 7 then 4x-4y equals?
3
What are the points of intersection when the line x -2y equals 1 crosses the curve 4y2 -3x2 equals 1?
If: x -2y = 1 then x = 1 +2y If: 4y^2 -3x^2 = 1 then 4y^2 -3(1 +2y)^2 -1 = 0 Removing brackets: 4y^2 -3 -12y -12y^2 -1 = 0 Collecting like terms: -8y^2 -4 -12y = 0 Dividing all terms by -4: 2y^2 +1 +3y = 0 Factorizing the above: (2y+1)(y+1) = 0 meaning y = -1/2 or y = -1 Therefore points of intersection by substitution are at: (0, -1/2) and (-1, -1)
