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What are the possible numbers that can be made with the digits 4 7 9 1 if each digit is used only once?
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∙ 11y ago
4719 - 1974 - 7491 - 7419 - 9147 - 9174 - 7914 - 7941 - 4917- 4971 - 4179- 4197
7194 - 7149 - 9417 - 9471 - 1479 -1497 - 4791 - 1947 - 1749 - 1794 -
9741 -9714 - (4791)
Wiki User
∙ 11y ago
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How many 4 digit numbers have 6 as their second digit?
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
What is the greatest possible 9 digit number that uses each of the digits 1-3 times?
what is the greets possible 9 digit number that uses each of the digits 1-3 times
What 5 digit number has Numbers increasing from the left Each digit is different 1st and 5th digits are square numbers 1st and 4th digits are cubed numbers 2nd 3rd digits are even?
12689 14689 12489
How many five digit numbers can you make with 23456?
You gave me 5 digits. -- The first digit can be any one of the 5 digits. For each one, -- The second digit can be any one of the remaining 4 digits. For each one, -- The third digit can be any one of the remaining 3 digits. For each one, -- The fourth digit can be any one of the remaining 2 digits. For each one, -- The fifth digit can only be the remaining 1 digit. So there are (5 x 4 x 3 x 2 x 1) = 120 possible different arrangements.
What is the total number of digits in the numbers from 1 to 1000000?
In the numbers 1-9 each number has 1 digit and there are 9 of them, so that's 9.In 10-99 each number has 2 digits, and there are 90 of them: 2x90 = 180There are 900 three digit numbers [100 through 999]: 2700 digits.There are 9000 four digit numbers: 36000 digits.90,000 numbers with five digits: 450,000 digits.900,000 numbers with six digits: 5,400,000 digits.Then 1 number with seven digits: 7 digits.Add them up and you have 5,888,896 digits.
How many 4 digit numbers have 6 as their second digit?
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
How many even four digit numbers can be made using 02356 where the first digit is cannot be 0 and no digits are repeated?
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
How many 3 digit counting numbers are not multiples of 5?
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
How many four digits numbers can be formed using 0123456789?
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
How many 4 digit numbers can be formed from digits 123456789?
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
What is the greatest possible 9 digit number that uses each of the digits 1-3 times?
what is the greets possible 9 digit number that uses each of the digits 1-3 times
What 5 digit number has Numbers increasing from the left Each digit is different 1st and 5th digits are square numbers 1st and 4th digits are cubed numbers 2nd 3rd digits are even?
12689 14689 12489
How many five digit numbers can you make with 23456?
You gave me 5 digits. -- The first digit can be any one of the 5 digits. For each one, -- The second digit can be any one of the remaining 4 digits. For each one, -- The third digit can be any one of the remaining 3 digits. For each one, -- The fourth digit can be any one of the remaining 2 digits. For each one, -- The fifth digit can only be the remaining 1 digit. So there are (5 x 4 x 3 x 2 x 1) = 120 possible different arrangements.
What are all the possible 5 digit codes using the numbers 0-9?
There are 10000 such codes. Each of the numbers 0-9 can be in the first position. With each such first digit, each of the numbers 0-9 can be in the second position. With each such pair of the first two digits, each of the numbers 0-9 can be in the third position. etc.
What is the total number of digits in the numbers from 1 to 1000000?
In the numbers 1-9 each number has 1 digit and there are 9 of them, so that's 9.In 10-99 each number has 2 digits, and there are 90 of them: 2x90 = 180There are 900 three digit numbers [100 through 999]: 2700 digits.There are 9000 four digit numbers: 36000 digits.90,000 numbers with five digits: 450,000 digits.900,000 numbers with six digits: 5,400,000 digits.Then 1 number with seven digits: 7 digits.Add them up and you have 5,888,896 digits.
What is the place value of each digit in 62.77147.40527?
It is not possible to answer the question since in standard form, numbers do not have points (full stops) that are five digits apart.
If you wrote all the possible four digit numbers made by using each of the digits 2 4 5 7 once (for example 7777 2244 etc) what would they add up to?
There are two possible answers as it is unclear what you mean by "using each of the digits 2 4 5 7 ONCE" in light of the examples you give (7777 and 2244): 1) The four digits {2, 4, 5, 7} may only be used once per 4 digit number: This is what would be understood by "...once" - no digit may appear more than once in any 4 digit number. For each position, there are 4 possible digits. When each digit is in a position, the other 3 digits can be arranged in 6 different ways. Thus each digit in the list of the 24 possible numbers appears in each position 6 times. Thus the sum of the digits in one position is 6 × (2 + 4 + 5 + 7) = 108 Thus the sum of all the possible 4 digit numbers is 108 × (1000 + 100 + 10 + 1) = 108 × 1111 = 119,998 2) The four digits {2, 4, 5, 7} may be used once, or may be repeated in each 4 digit number: This is what your example of "7777" (which has the digit 7 used more than once) suggests, contrary to your statement that each digit can only be used once. There are 256 possible numbers. In this case each digit appears in each position 64 times. Thus the sum is 64 × (2 + 4 + 5 + 7) × 1111 = 1,279,872
