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Q: What are the roots of the following equation x2 plus 6x plus 2 equals 9?

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The roots are: x = -5 and x = -9

This quadratic equation has no real roots because its discriminant is less than zero.

-2x plus 3y equals 1

It has roots x = 2.618 and x = 0.38197

There are no real root. The complex roots are: [-5 +/- sqrt(-3)] / 2

Solve the following equation for A : 2A/3 = 8 + 4A

The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842

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x = 2 and x = 4

The discriminant is -27 and so there are no real roots.

The discriminant of the equation ... (b2-4ac) = (225-160) ... is real and positive, so the roots are real and unequal.

If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.

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