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When multiplying, the number of significant numbers in the answer should be the same as the fewest significant figures in the problem. Both 13.5 and 3.00 have three significant figures, so the answer will have three significant figures. 13.5 x 3.00 = 40.5 exactly (no need to round).
For 25600.0, shift 4 decimal places to the left. Then, 2.56 x 104 has 3 sig figs, which are rounded up "already".
There are 2 significant figures in 7.8x109^?
There are two significant figures which are the 5 and the 4. 0.054 = 5.4 x 10^-2
Two of them.
6.5211 x 104 = 678.1944 678.1944 has 7 significant figures
Assuming that the number in question is 7.99*104, the answer is 3.
There are 5 significant digits in 78000. Which is the same as 7.8 x 104.
5 significant figures Each figure that contributes to the accuracy of a value is considered significant. So 2.9979 has 5 significant figures. The 10^8 does not contribute to the accuracy as it simply indicates the number of trailing zeroes (i.e. 299,790,000) that are simply a result of rounding from the actual value (299,792,458)
4.884 has four significant figures and 2.25 has three significant figures. 4.884 x 2.25 = 10.989 = 11.0 rounded to three significant figures. When multiplying or dividing, the result must have the same number of significant figures as the number in the problem with the fewest significant figures.
Significant figures are very important when it comes to calculations. If the mass of an electron is 9.10939 x 10-31 then its significant figures are: 9 x 10^-31( correct 1 significant figure), 9.1 x 10^-31 kg ( correct to 2 significant figures), 9.11 x 10^-31 (correct to 3 significant figures), and 9.109 x 10^-31 (correct to 4 significant figures).
It has 5 significant figures - one trailing zero is significant.
When multiplying, the number of significant numbers in the answer should be the same as the fewest significant figures in the problem. Both 13.5 and 3.00 have three significant figures, so the answer will have three significant figures. 13.5 x 3.00 = 40.5 exactly (no need to round).
29.05 to 3 significant figures
For 25600.0, shift 4 decimal places to the left. Then, 2.56 x 104 has 3 sig figs, which are rounded up "already".
There are 2 significant figures in 7.8x109^?
There are two significant figures which are the 5 and the 4. 0.054 = 5.4 x 10^-2