Numbers do not "have" other numbers. It's impossible to tell what this question is asking.
Let the three numbers be 'n' , 'n+1', & n+2 ' . (consecutive). Summing n + n+1 + n+ 2 = 48 3n + 3 = 48 Subtract '3' from both sides 3n = 45 Divide both sides by '3'. n = 15 The smallest number. NB THe other two numbers are 15 + 1 = 16 & 15 + 2 = 17
The smallest is 14.
x+ (x+1) + (x+2) = 48 3x+3 = 48 3x = 45 x = 15
There are infinite numbers but if you mean integers then they are 45 46 47 48 and 49
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
The answer is 48.
The numbers 48 and 15 both go into their least common multiple (LCM), which is 240. This means that 240 is the smallest positive integer that is divisible by both 48 and 15. Additionally, any multiple of 240 will also be divisible by both numbers.
The least common factor is the smallest factor that two or more numbers have in common. Thus, the least common factor of two numbers is 1. The least common factor of 48 and 116 is 1.
The smallest number that is divisible by 18 and 48 is 144.
The least common multiple is the smallest number that is multiple of two or more numbers. 48: 48, 96, 144 72: 72, 144 The LCM of of 48 and 72 is 144.
The least common multiple (LCM) of two or more numbers is the smallest number (not zero) that is a multiple of all. The LCM of 19, 47 and 48 is 42,864
24. eg 24, 48, 72 or 24, 264, 2904