To solve a quadratic equation (which means to find the zeros of that equation) you have two options
1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0)
2. solve the quadratic equation by factoring
First, set the equation equal to zero.
x2-8x-9=0
Then find the resulting x values by "smiling"
multiply the first term and the last term (x2) (9)
find two numbers that add to -8 and multiply to -9
these two numbers are -9 and 1
x2- 9x 1x-9
x(x-9) 1(x-9)
the resulting factors are 0= (x+1)(x-9)
to find the roots, set these factors = 0
x+1=0
x=-1
x-9=0
x=9
Therefore, the solutions for the quadratic equation are x=-1 and x=9
It is a quadratic equation and its solutions are: x = -3/2 and x = 3
It is a quadratic equation and its solutions are: x = 4 or x = -9
Using the quadratic equation formula:- x = 1 +/- the sqrt of 13 = -2.60555 and 4.60555 (to 5 dp).
It is a quadratic equation and its solutions are: x = 3 and x = 5
The quadratic equation in standard form is: ax2 + bx + c = 0. The solution is x = [-b ± √b2- 4ac)] ÷ 2a You can use either plus or minus - a quadratic equation may have two solutions.
The solutions to the quadratic equation are: x = -1 and x = 6
It is a quadratic equation and its solutions are: x = -3/2 and x = 3
It is a quadratic equation and its solutions are: x = 4 or x = -9
Using the quadratic equation formula:- x = 1 +/- the sqrt of 13 = -2.60555 and 4.60555 (to 5 dp).
It is a quadratic equation and its solutions are: x = 3 and x = 5
The quadratic equation in standard form is: ax2 + bx + c = 0. The solution is x = [-b ± √b2- 4ac)] ÷ 2a You can use either plus or minus - a quadratic equation may have two solutions.
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
If you mean 5x^2 -7x +2 = 0 then it is a quadratic equation with solutions of x = 2/5 or x = 1
Without an equality sign and not knowing the plus or minus value of 11 it can't be considered to be an equation.
Using the quadratic equation formula: x = -2 plus or minus the square root of 6 which means that x = 0.4494897427831779 x = -4.4494897427831779
Plug 'a', 'b', and 'c' from the equation into the formula. When you do that, the formula becomes a pair of numbers ... one number when you pick the 'plus' sign, and another number when you pick the 'minus' sign. Those two numbers are the 'solutions' to the quadratic equation you started with.
The equation has infinitely many solutions.